Subnetting Exercises

In this exercise, I will teach you how to create subnets for a certain network address.

A. Company ABC has 100 workstations in their head office and the IT manager would like to assign a subnetwork address for each department. He wants to create 5 subnets using the 192.168.1.0/24 block and assign the first subnetwork to their servers and the rest for their 100 workstations. How will we compute the subnetwork requirement?

Given:
Number of workstations = 100
Network address = 192.168.1.0/24
Subnets required = 5
*Note: Subnetwork 1 will be allotted for the servers

Solution to the problem:
By default, the class C address of 192.168.1.0 has a default subnet mask of 255.255.255.0 or /24. This kind of address has 24 network bits (192.168.1) and 8 available hosts bits indicated by the (0) on the last portion of the network address. By default also your available hosts bits is (2^8) -2 or equals 254 hosts bits. Take note that we subtract 2 from the equation because the total bits is 256 but 2 addresses are used for the network address (192.168.1.0) and broadcast address (192.168.1.255) respectively.

Since the requirement is 5 subnets, we will borrow 3 hosts bits and make it part of the network bits. Next we will add the 3 borrowed bits to the current network address bits (24) and our output now will be 27 network bits and 5 remaining hosts bits. Since we borrow 3 hosts bits our newly subnet mask is 255.255.255.224 or /27.

Now that we already determine the subnet mask for our newly created subnetworks, we will now determine how many hosts per subnetwork address are available. We have 5 remaining hosts bits (2^5) -2 we have 30 hosts per subnets. Let us determine the subnet addresses of our new network:

Subnet 1: 192.168.1.0 – 192.168.1.31 (usable 192.168.1.1 – 192.168.1.30)
Subnet 2: 192.168.1.32 – 192.168.1.63 (usable 192.168.1.33 – 192.168.1.62)
Subnet 3: 192.168.1.64 – 192.168.1.95 (usable 192.168.1.65 – 192.168.1.94)
Subnet 4: 192.168.1.96 – 192.168.1.127 (usable 192.168.1.97 – 192.168.1.126)
Subnet 5: 192.168.1.128 – 192.168.1.159 (usable 192.168.1.129 – 192.168.1.158)
Subnet 6: 192.168.1.160 – 192.168.1.191 (usable 192.168.1.161 – 192.168.1.190)
Subnet 7: 192.168.1.192 – 192.168.1.223 (usable 192.168.1.193 – 192.168.1.222)
Subnet 8: 192.168.1.224 – 192.168.1.255 (usable 192.168.1.225 – 192.168.1.254)

We have created 8 subnetwork addresses to be used for Company ABC and they only require 5 subnets for their network infrastructure. There are still 3 more available subnets for future use.

  1. February 22, 2013 at 23:49 | #1

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